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    Question

    The sum of the exponents of the prime factors in the

    prime factorization of 108 is
    A 5 Correct Answer Incorrect Answer
    B 2 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer

    Solution

    ATQ, LetтАЩs break 108 into prime factors: 108 = 2 ├Ч 2 ├Ч 3 ├Ч 3 ├Ч 3 So, 108 = 2┬▓ ├Ч 3┬│ Then, add the exponents: The exponent of 2 is 2. The exponent of 3 is 3. Total = 2 + 3 = 5. Hence, 5 is the answer.

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