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      Question

      The sum of the exponents of the prime factors in the

      prime factorization of 108 is
      A 5 Correct Answer Incorrect Answer
      B 2 Correct Answer Incorrect Answer
      C 6 Correct Answer Incorrect Answer
      D 8 Correct Answer Incorrect Answer

      Solution

      ATQ, Let’s break 108 into prime factors: 108 = 2 × 2 × 3 × 3 × 3 So, 108 = 2² × 3³ Then, add the exponents: The exponent of 2 is 2. The exponent of 3 is 3. Total = 2 + 3 = 5. Hence, 5 is the answer.

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