Question
Determine the value of 'a' such
that the number 102a32 is divisible by 48.Solution
ATQ,
48 = 2 × 3 × 8 So, 102a32 is divisible by both 3 and 8 Since 102a32 is divisible by 3, so sum of the digits must be divisible by 3 So, (1 + 0 + 2 + x + 3 + 2) = (a + 8) must be divisible by 3 So, (a + 8) = 9 or 12 or 15 So, a = 1 or 4 or 7 For 102a32 to be divisible by 8, a32 must be divisible by 8 So, a = 2 or 4 or 6 or 8 Since the number is divisible by both 3 and 8, So a = 4
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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