Question
Determine the number of trailing zeros in the product of
the following numbers: 11 × 22 × 33 × … × 2222Solution
Total number of 5’s in the given expression: 55 = 15 × 55 = 5 1010 = 210 × 510 = 10 1515 = 315 × 515 = 15 2020 = 420 × 520 = 20 Total number of 2’s in the given expression: 22 = 2 44 = (22)4 = 28 = 8 66 = (2 × 3)6 = 26 × 36 = 6 88 = (23)8 = 224 = 24 1010 = 210 × 510 = 10 So, total number of 5’s in the given expression = 5 + 10 + 15 + 20 = 50 And, at least 50 2’s in the given expression So, number of zeroes at the end of the product = 50Â
Section 39 of Insurance Act related with which of the following ?
What is a form of non-proportional reinsurance?
The 'Insured Declared Value' (IDV) of a vehicle refers to its:
If you might want to discontinue the policy, and take whatever money is due to you. The amount the insurance company then pays is known as?
If an organization wishes to venture into Insurance Business it has to obtain a licence firstfrom which of the following ?
An extension of endowment plans is known as which policy?
Which is not a General Insurance company?
The first motor vehicle insurance policy was issued in the UK in:
What does IRDA mandate for surveyors handling losses above INR 20,000?
Coverage for property taken or destroyed by breaking and entering the insured’s premises, burglary or theft, forgery or counterfeiting, fraud, kidnap ...
