Question
A car rental company offers two types of packages:
Package X and Package Y. Package X charges a base fee of ₹300 per day plus ₹10 per kilometer. Package Y charges ₹500 per day and includes 30 kilometers per day. For how many kilometers does the total cost of Package X equal the total cost of Package Y?Solution
Let the number of kilometers be x. For Package X: Cost = 300 + 10x For Package Y: Cost = 500 + 0 (since the first 30 km are included). To find the break-even point, set the costs equal: 300 + 10x = 500 10x = 200 x = 20 km Answer: b) 20 km
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value should come in the place of (?) in the following questions?
908.90 –190.32 + √? = 23.03 * 5.2 + 24.72
? = (7.11/2.12) + (10.88/4.09) + (45.12/11.98)
? = {29.7% of (97.72 × 40.04)} ÷ 3.92
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
111.89 × 4.12 – 504.04 ÷ 2.12 = 170.12 + ?
√49 + 6.66% of 1725 + 22² = ?² - √361
[(√2024.85 ÷ 3.01) + (35.76 ÷ 11.92)]² × (3/4 of 39.99) = ?
(88.931% of 435) + (61.521% of 516) = ?
14.232 + 19.98% of 629.99 = ? × 6.99