‘479385A267’ is ten-digit number which is divisible by 9, what is the value of ‘A’?
Divisibility by ‘9’: Sum of the digits must be divisible by ‘9’. So, (4 + 7 + 9 + 3 + 8 + 5 + A + 2 + 6 + 7) must be divisible by ‘9’ Or, (51 + A) must be divisible by 9. So, A = 3
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