Question
A 40 L mixture contains milk and water in the ratio 5:3.
How many litres of the mixture should be removed and replaced with water so that the new mixture contains 50% milk?Solution
ATQ, Initial milk = (5/8) of 40 = 25 L After replacement, milk must be 50% of 40 = 20 L Milk reduced = 25 − 20 = 5 L If x litres removed, milk removed = (5/8)x So (5/8)x = 5 ⇒ x = 8 L
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