Question
A container is completely filled with 60 litres of pure
milk. First, 20 litres of milk is taken out and replaced with water. Then again, 20 litres of the resulting mixture is taken out and replaced with water. How much milk is left in the container now?Solution
Let total volume = 60 L, amount replaced each time = 20 L Fraction of milk left after one operation: = (1 − 20/60) = (40/60) = 2/3 After 2 operations, fraction of milk left: = (2/3)² = 4/9 Milk left = 60 × (4/9) = 240 / 9 ≈ 26.67 litres
- What will come in place of the question mark (?) in the following questions?
300−40% of 200=? - Simplify the following expression:
16 + [17 - (8 + 11) + 6 - 3] ÷ 0.2 Simplify the following expression.
(3-3 × 3 + 3 ÷ 3 + 3 × 5) × 2 of 5 + (2 + 2 ÷ 2 + 2 × 2 - 2)
2/9 of 5/8 of 3/25 of ? = 40
115 ÷ 23 + 12 × 6 = ? + 16 - 35
√? = 32% of 900 + 48% of 50
 Â
5/13 × 104 + 1(2/9) × 198 = 133 + ?
Simplify the following expressions and choose the correct option.
40% of 360 + 25% of 248 - 30
(11/12) × (18/22) × (4/3) + 3 = ?2
[(15)³ × (8)²] ÷ (90 × 6) = ?²