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ATQ,
260 liters of solution contains 140 liters of milk and 120 liters of water.
x liters of solution contains (7x/13) liters of milk and (6x/13) liters of water.
(140 – 7x/13) / (120 – 6x/13 + 20) = 4/5
(1820 – 7x) / (1820 – 6x + 260) = 4/5
(1820 – 7x) / (2080 – 6x) = 4/5
5(1820 – 7x) = 4(2080 – 6x)
9100 – 35x = 8320 – 24x
11x = 780
x = 70
So, the value of ‘x’ is 70 liters.
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