Question
In a 120-litre chemical mixture, the chemicals A and B are
in the ratio 5:7. How much of chemical A must be added to make the ratio 7:7 (i.e., equal amounts)?Solution
ATQ,
Quantity of A = (5/12) × 120 = 50 litres
Quantity of B = (7/12) × 120 = 70 litres
Let the amount of A to be added be x litres
Then, (50 + x) : 70 = 7 : 7
So, 50 + x = 70
x = 70 - 50 = 20 litres
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Find the approximate value of Question mark(?). No need to find the exact value.
24.95 × (36.06 ÷ 6) + 74.95% of 159.89 – √(143.94) × 2....
(18.31)2 – (13.68)2 + (2344.20 + 82.32) ÷ ? = 229.90
32.12% of 2399.98 + 64.04% of 2499.95 = ? × 15.95
(21.02 × 5.83 × 12.03 ÷ 6.99 of 4.03) + 31.93% of 50.03 = ?
20.22% of (61.9 × 5.01) + 69.97 =?
29.81 % of 49.91 + 14.28% of 147.09 + 179.91 = ?3
?² × 55% of (29 + 32 - 41) = 41.66% of 216 + 9
? = 28.04² ÷ (4.01⁵ + 9.89 × 20.20) + 84.56% of (198.76 × 30.03)
(10.98% of 499.99) - 4.998 = √?
