There are two mixtures, 'E' and 'F' of alcohol and water. Total quantity of mixture 'E' and mixture 'F' are 8 litres and 18 litres, respectively. Mixture 'E' contains 20% alcohol, while mixture 'F' contains 45% alcohol. Some amount of alcohol is added to mixture 'E', such that the percentage of quantity of alcohol in the resultant mixture becomes 50%. Same quantity of alcohol is also added to mixture 'F'. If both the resultant mixtures are mixed together, then find the total quantity of alcohol in the mixture.

ATQ; Initial quantity of alcohol in mixture 'E' = 0.2 X 8 = 1.6 litres Initial quantity of water in mixture 'E' = 8 - 1.6 = 6.4 litres Let the quantity of alcohol added to the mixture be 'x' litres. Since the quantity of water in the final mixture of mixture 'E' remains the same. So, Quantity of water in the final mixture of mixture 'E' = 0.50 X (8 + x) = 6.4 Or, 8 + x = (6.4 / 0.50) Or, x = 12.8 - 8 So, x = 4.8 Quantity of alcohol in the resultant mixture of mixture 'E' = (1.6 + x) = 1.6 + 4.8 = 6.4 litres Initial quantity of alcohol in mixture 'F' = 0.45 X 18 = 8.1 litres Final quantity of alcohol in mixture 'F' = 8.1 + 4.8 = 12.9 litres Therefore, the quantity of alcohol when the final mixtures of mixture 'E' and mixture 'F' are added together = 6.4 + 12.9 = 19.3 litres