There are two mixtures, 'E' and 'F' of alcohol and

Solution

ATQ; Initial quantity of alcohol in mixture 'E' = 0.2 X 8 = 1.6 litres Initial quantity of water in mixture 'E' = 8 - 1.6 = 6.4 litres Let the quantity of alcohol added to the mixture be 'x' litres. Since the quantity of water in the final mixture of mixture 'E' remains the same. So, Quantity of water in the final mixture of mixture 'E' = 0.50 X (8 + x) = 6.4 Or, 8 + x = (6.4 / 0.50) Or, x = 12.8 - 8 So, x = 4.8 Quantity of alcohol in the resultant mixture of mixture 'E' = (1.6 + x) = 1.6 + 4.8 = 6.4 litres Initial quantity of alcohol in mixture 'F' = 0.45 X 18 = 8.1 litres Final quantity of alcohol in mixture 'F' = 8.1 + 4.8 = 12.9 litres Therefore, the quantity of alcohol when the final mixtures of mixture 'E' and mixture 'F' are added together = 6.4 + 12.9 = 19.3 litres