Question
Quantity I: An amount is to be distributed among A, B,
and C in the ratio 1:3:2 respectively, but was erroneously distributed in the ratio 2:7:9 due to which B got Rs.136 less. What is the amount to be distributed? Quantity II: Rs.1228 In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity I and Quantity II and choose the correct option.Solution
Real ratio = (1 + 3 + 2) = 6 Incorrect ratio = (2 + 7 + 9) = 18 Let amount be 18x (L.C.M of 6 and 18) Amount to be received by B = 18x/6 × 3 = 9x Amount erroneously received by B = 18x/18 × 7 = 7x Difference = 9x - 7x = 2x ∴  2x = 136 ⇒  x = 68 So, Amount = 18x = 18 × 68 = Rs.1224 Quantity II: Rs.1228 Hence, Quantity I < Quantity II
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