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Question

Direction: The question consists of two quantities, choose the correct option which represents the   correct relation between Q1 and Q2.

Quantity I(Q1) : A mixture of water, milk and honey contains 44 litres more water than milk in it. Also the quantity of honey in it taste 30% less than that of water in it. If half of the mixture is replaced with 18 litres of milk, then the ratio of quantities of milk and honey in the restaurant. Mixture, resultant, mixture. Becomes four ratio 3 respectively. Milk and honey together form how much proportion of the original mixture?

Quantity 2(Q2) : A box has three red balls, two green balls, 2 blue balls and five yellow balls. If two balls are picked at random from the box, what is the probability that two balls are not of the same color?

A Q1>Q2 Correct Answer Incorrect Answer
B Q2>Q1 Correct Answer Incorrect Answer
C Q1<= Q2 Correct Answer Incorrect Answer
D Q1>=Q2 Correct Answer Incorrect Answer
E Q1=Q2 or cant be determine Correct Answer Incorrect Answer

Solution

Let the original quantity of water in the mixture = 10y lt. Then original quantity of milk in the mixture= (10y-44) lt. Original quantity of honey in the mixture= 10y*(1-0.3)= 7y lt. After replacing half of the mixture with 18 litres of milk, Quantity of milk in the resulting mixture = (10y-44)/2 +18 = 5y-4 lt. After replacing half of the mixture with 18 litres of milk, quantity of honey in their resultant  mixture = 7y/2 = 3.5y lt. As per the question, 5y-4 : 3.5y = 4:3 15y-12 = 15y y= 12 So original   quantity of water, milk and honey in the mixture is 6. Litre and 84 liter respectively. So required proportion = (76+84)/(120+76+84) = (4/7)

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