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Let the original quantity of water in the mixture = 10y lt. Then original quantity of milk in the mixture= (10y-44) lt. Original quantity of honey in the mixture= 10y*(1-0.3)= 7y lt. After replacing half of the mixture with 18 litres of milk, Quantity of milk in the resulting mixture = (10y-44)/2 +18 = 5y-4 lt. After replacing half of the mixture with 18 litres of milk, quantity of honey in their resultant mixture = 7y/2 = 3.5y lt. As per the question, 5y-4 : 3.5y = 4:3 15y-12 = 15y y= 12 So original quantity of water, milk and honey in the mixture is 6. Litre and 84 liter respectively. So required proportion = (76+84)/(120+76+84) = (4/7)
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