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    Question

    The question consists of two quantities, choose the

    correct option which represents the. correct relation between Quantity I and Quantity II. Quantity I  . A&B invested their sum in the ratio of 22: 25. Respectively. In two different schemes. Offering simple interest of 15% per annum and compound interest of 12% per annum. Respectively. Such that interest received by A. At the end of three years was rupees 1062 more than that by B at the end of two years? Find this sum invested by A. Quantity II. A and C started a business as this sum invested by A is rupees 600 more than that by C Two months later, B joined them with an investment that is 30% less than that of A if the annual profit share of A was 25% less than the sum of annual profit share of B&C. Then find the average of investment of A, B and C.
    A Quantity I > Quantity II Correct Answer Incorrect Answer
    B Quantity I < Quantity II Correct Answer Incorrect Answer
    C Quantity I ≤ Quantity II Correct Answer Incorrect Answer
    D Quantity I ≥ Quantity II Correct Answer Incorrect Answer
    E Quantity I = Quantity II or No relation Correct Answer Incorrect Answer

    Solution

    Let the sum invested by A&B be rupees 22y and rupees 25y respectively. Then interest received by A = 22y*15*3/100 = Rs. 9.9y Interest received by B = 25y{1+(12/100)} 2 –25y = Rs. 6.36y According to question, 9.9y-6.36y = 1062 y=300 So some invested by A = 22*300 = Rs. 6600 Quantity 2 Let the investment of A = Rs. 10y Then investment of C = Rs. 10y –600 Investment of B = Rs. 7y Ratio of annual profit shares of A, B and C respectively = (10y*12):( 7y*10):{(10y-600)*12} = 120y:70y:(120y-7200). We have (70y+120y-7200)*0.75 = 120y 142.5y-5400=120y 22.5y=5400 y=240. So investment amount of A, B, C is Rs. 2400, Rs. 1680, Rs. 1800 respectively. So required average = (2400+1680+1800)/3 = Rs. 1960

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