Question
In a mixture, the quantity of salt is 40% of the
quantity of water. On removing 90 litres mixture and adding 20 litres each of salt and water, the quantity of salt becomes 30 litres less than that of water in the final mixture. Find the final quantity of water.Solution
ATQ, After removal of 90 litres of mixture, Let the initial quantity of water be '100b' litres. Initial quantity of salt = 0.4 Γ 100b = '40b' litres. ATQ, 100b - 40b = 30 Or, 60b = 30 Or, 'b' = 30/60 = 0.5 Therefore, final quantity of water = 100b + 20 = 100 Γ 0.5 + 20 = 50 + 20 = 70 litres
(480 + 340 - ?) Γ (3/19) = 90Β
- What will come in place of the question mark (?) in the following questions?
0.5Γ120+25=? 1.55 + 2.05 + 1.5 × 11 – 20% of 10.5 = ?
What will come in place of the question mark (?) in the following expression?
?% of 600 + 15 Γ 28 = 30% of 1800
β324 + β484 + 63 = ?2Β
240 Γ 2.5 + 65 Γ 2/13 = ?2 - β225
Find the value of βyβ if (2/7) Γ y = 0.79 β 1.77 Γ· 3.
20 * 8 + 40% of 100 + 60% of 150 = ?
325934.78 + 78545.30 + 92.25 =?
- What will come in the place of question mark (?) in the given expression?