Question
Mixture 'P,' comprising both milk and water, is
combined with another mixture 'Q' (consisting of milk and water) in a ratio of 3:2, respectively. The ratio of milk to water in mixture 'Q' is 5:1. If the resulting mixture has a milk to water ratio of 17:7, determine the ratio of milk to water in mixture 'P.'Solution
ATQ, Let, the fraction of quantity of milk in mixture 'P' be (a/b) . Fraction of milk in mixture 'Q' = [5/(5 + 1) ] = (5/6) = (20/24) Fraction of milk in the resultant mixture = [17/(17 + 7) ] = (17/24) (1/8) :[(17/24) - (a/b) ] = 3:2 Or, 2 × (1/8) = 3 × [(17/24) - (a/b) ] Or, (1/4) = (17/8) - 3 × (a/b) Or, 3 × (a/b) = (17/8) - (1/4) Or, 3 × (a/b) = (15/8) Or, (a/b) = (15/8) × (1/3) So, (a/b) = (5/8) So, the ratio of milk and water in mixture 'brown rice' = 5:(8 - 5) = 5:3
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...
Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is: