Start learning 50% faster. Sign in now
ATQ, For statement I: Let quantity of juice and water in mixture X is '5x' ml and 4x ml respectively. Quantity of juice and water in mixture Y is '7y' ml and 9y ml respectively. So, 9x + 16y = 590..........................(1) And, 9y – 4x = 60.........................(2) Solving equation (1) and (2), we get x = 30 and y = 20 So, desired ratio = 150:140 = 15:14 So, statement I is true For statement II: Let quantity of juice and water in mixture X is '5x' ml and 4x ml respectively. Quantity of juice and water in mixture Y is '7y' ml and 9y ml respectively. So, 9x + 16y = 756..........................(1) And, 9y – 4x = 99.........................(2) Solving equation (1) and (2), we get x = 36 and y = 27 So, desired ratio = 180:189 = 20:21 So, statement II is true For statement III: Let quantity of juice and water in mixture X is '5x' ml and 4x ml respectively. Quantity of juice and water in mixture Y is '7y' ml and 9y ml respectively. So, 9x + 16y = 1080..........................(1) And, 9y – 4x = 100.........................(2) Solving equation (1) and (2), we get x = 56 and y = 36 So, desired ratio = 280:252 = 10:9 So, statement III is true. For statement IV: Let quantity of juice and water in mixture X is '5x' ml and 4x ml respectively. Quantity of juice and water in mixture Y is '7y' ml and 9y ml respectively. So, 9x + 16y = 1608..........................(1) And, 9y – 4x = 252.........................(2) Solving equation (1) and (2), we get x = 72 and y = 60 So, desired ratio = 360:420 = 6:7 So, statement IV is not true
(799.81/64)÷ (10/799.92) × (129.84/130) = ?
...120.982-√675×5+1422.20÷9.02=?
54.97% of 620.08 + 16.13 × 11.11 – 829.91 ÷ 5 = ?
√49 + 6.66% of 1725 + 22² = ?² - √361
√? + √626 × 13.998 - 6.02 × 2.97 = 345.995
28.01% of 3650 + 40.10% of 150 – 301.75 = ?
(22.93 × 11.92) + (17.78 ÷ 3.01) - (14.88 × 5.01) = ?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
(√4623.9 + √484.2) – √2303.97 ÷ √1296.4 × √35.98 ÷ √15.99 = ?