Question
A mixture of lime and water contains 3a liters lime and
(a + 40) liters water. Upon adding 20 liters more water, the ratio of quantity of water to that of lime in the mixture becomes 2:3. How much water should be added in the resultant mixture to further decrease the % of quantity of lime in the mixture to 50%?Solution
ATQ, we can say that {(3a)/(a + 40 + 20)} = (3/2) Or, 6a = 3a + 180 Or, 3a = 180 So, a = 60 So, quantity of milk present in the mixture = (60 × 3) = 180 liters And quantity of water present in the mixture = 60 + 40 + 20 = 120 liters So, quantity of mixture after more water is added = (180/0.5) = 360 liters So, quantity of water to be added = 360 - 300 = 60 liters
26.11% of ? – 521.02 = 648.51
44.87% of (39.85 × ?) – 1520.88 0.51 = 1400.8
√49 + 6.66% of 1725 + 22² = ?² - √361
What is the value of "π"
√3601 × √(224) ÷ √102 = ?
A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1620 and simple interest of Rs.1500 at the end of 2 year...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(18.22) 2.02 + (13.89) 2.12 – (44.88) 2.07 = ? – 1604.85
What approximate value should come in the place of (?) in the following questions?
...
(8160.42 ÷ 33.73) + 309.79 + ? = 30.2 * 81.84What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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