Question
A mixture contains oil and water in the ratio 7:5. When
70% of this mixture is replaced with 153 litres of water, the ratio becomes 8: 13. Than, what will be the quantity of original mixture?Solution
Ratio of oil and water = 7 : 5 (Initially) Ratio of oil and water = 8 : 13 (After adding 153 litres water) Equating oil from the mixture:- Ratio of oil and water = 56 : 40 (Initially) Ratio of oil and water = 56 : 91 (After adding water) 51 units = 153 litres 1 units = 3 litres Initially quantity of mixture = 96 x 3 = 288 30% -- 288 litres therefore, orginal mixture will be = 100 % --- 960 litres
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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