Question
55 litres of a solution contains alcohol and water in
the ratio 2:3. Water is added in the solution. The new mixture has a ratio of alcohol and water as 1:5. Find the quantity of water added.Solution
Let initial quantity of alcohol and water be 2x and 3x. ⇒  2x + 3x = 55 ⇒  5x = 55 ⇒  x = 11 Initial quantity of alcohol = 2x ⇒  22 litres Initial quantity of water = 3x ⇒  33 litres Let the water to be added be x litres. 22/(33 + x) = 1/5 ⇒  110 = 33 + x ⇒  77 = x Therefore, quantity of water added is 77 litres.
l). 3p + 2q = 27
ll). 4p - 3q = 2
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What will be the product of smaller roots of both equations.Â
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Equation 2: 2y² + 8y + 6 = 0
I. 63x2 + 148x + 77 = 0
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I. 8y2 - 2y - 21 = 0
II. 2x2 + x - 6 = 0
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II. 3y2 – 29y + 18 = 0
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