Question
200 litres of mixture contains water and milk in the
ratio 3:5 respectively. If 120 litres of the mixture is replaced by same quantity of water, then find the ratio of water and milk in the final mixture.Solution
Remaining quantity of the original mixture = 200 – 120 = 80 litres Quantity of water in the final mixture = 80 x (3/8) + 120 = 150 litres Quantity of milk in the final mixture = 80 x (5/8) = 50 litres Ratio of water and milk in the final mixture = 150 : 50 = 3:1
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2