Question
A 60-litre mixture contains only water and oil in the
ratio 5:1, respectively. If 36 litres of the mixture is replaced with the same quantity of oil, then find the quantity of oil in the final mixture.Solution
Amount of oil in the mixture = 60 × (1/6) = 10 litres Amount of oil withdrawn = 36 × (1/6) = 6 litres Quantity of oil in the final mixture = 10 – 6 + 36 = 40 litres
If a = 701, b= 703 and c= 706, then find the value of a³ + b³ +c³ –3abc?
If (a – 8) 2 + (b + 2) 2 + (c – 3) 2 = 0, then find the value √(a +b + c).
...(a – 2) 2 + (b + 6) 2 + (c – 1) 2 = 0, then find the value of a + b – c.
- Suppose [a + (1/16a)] = 3, then the value of [16a³ + (1/256a³)] is:
- If (m + n + o) = 16 and (mn + no + om) = 80, then find the value of (m² + n² + o²).
If 3x + (1/3x) = 8 then find 27x3 + (1/27x3) = ?
If √b + (1/√b) = 8, then find the value of b + (1/b).
If a3 — b3 = 602 and a— b = 2, then find the value of( a2 + b2)
(44² × 16²) ÷ (184.8 ÷ 8.4) =? × 64
If ( p = 40 - q - r ) and ( pq + r(q + p) = 720 ), then find the value of ( p2 + q2 + r2).