Question
A rectangular garden is 30 m long and 24 m wide. A path
of uniform width 2 m is built inside along the boundary of the garden. Find the area of the path.Solution
Outer rectangle dimensions: 30 × 24 → area = 720 m² Inner rectangle (after 2 m path on all sides): Length = 30 − 4 = 26 m Width = 24 − 4 = 20 m Inner area = 26 × 20 = 520 m² Area of path = outer area − inner area = 720 − 520 = 200 m² Answer: 200 m².
- If p = 25 - q - r and pq + r(p + q) = 256, then find the value of (p² + q² + r²).
If 27x3 - 8y3 = (3x - Ay) X (Bx2 + 4y2 + Cxy), then find the value of 3 X (2A + 6B) - 2C.
If, 6x + y = 20, and 2xy = 32, and 6x > y, then find the value of 216x³ – y³.
If ab + bc + ca = 0
Find the value of 1/(a2 - bc) + 1/(b2 - ca) + 1/(c2 - ab)
If A = (7)1/3 + (7) -1/3, then the value of {3A3 – 9A} will be:
- If 2a - 3b = 8 and ab = 7, then find the value of 2a + 3b.
 + Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
Atul has Rs.500 with him. He invested 30% of the amount at 5% p.a. for 6 years and rest at 20% p.a. for 4 years. Find the sum of simple interests receiv...
Simplify the expression:
3x + 5y - [(7x + 3y) - (2x + y) + 4y] - x
Relevant for Exams:
