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ATQ,
TSA = 2 × π × r × (r + h)
So, 2 × (22/7) × 22 × (22 + height) = 6,160
Or, 22 + height = 28
Or, height = 6 cm
Now, k - 5 = 6
Or, k = 11
Required value = 11² = 121
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