Question
A cylindrical road roller has a diameter of 2.2 metres and
a length of 1.75 metres. If it moves with 14 revolutions per minute, how much area does it roll over in 12 minutes?Solution
ATQ,
CSA = 2 × π × radius × height
= 2 × (22/7) × (2.2/2) × 1.75
= 2 × (22/7) × 1.1 × 1.75 = (84.7/7) m²
Area in 1 minute = 14 × (84.7/7) = 1,185.8/7 m²
Area in 12 minutes = 12 × (1,185.8/7) = 14,229.6/7 = 2,032.8 m²
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