Question
What is the edge length of the cube whose volume is
1016 cm3 more than the sum of volumes of cubes having edge lengths of 6 cm, 8 cm and 10 cm.Solution
Volume of cube having edge length of 6 cm = 6 X 6 X 6 = 216 cm3 Volume of cube having edge length of 8 cm = 8 X 8 X 8 = 512 cm3 Volume of cube having edge length of 10 cm = 10 X 10 X 10 = 1000 cm3 Let the edge length of the cube be 'a' cm. ATQ, a3 = 216 + 512 + 1000 + 1016 = 2744 So, 'a' = 14 Required edge length = 14 cm
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34 : 408
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