Question
The perimeter of a sector of a circle, whose radius is
20 cm, is 60 cm. If the length of a rectangle is 10 cm more than the arc subtended by the sector and its perimeter is 66 cm, then find the area (in cm2) of the rectangle.Solution
Let the arc subtended by the sector be ‘l’ cm and the radius of the circle be ‘r’ cm According to the question, (l + 2r) = 60 Or, l = 60 – 2r = 60 – (2 × 20) = 20 cm Therefore, length of the rectangle = 20 + 10 = 30 cm Let the breadth of the rectangle be ‘b’ cm Therefore, 2 × (30 + b) = 66 Or, b = 33 – 30 = 3 cm Therefore, area of the rectangle = length × breadth = 3 × 30 = 90 cm2
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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