Question
The length and breadth of a rectangular field are
increased by 25% and 45%, respectively. If the original dimensions of the field are 60 m in length and 40 m in breadth, what is the percentage increase in the perimeter?Solution
Original perimeter of rectangular field = 2 × (60 + 40) = 200 m Increased length of rectangular field = 1.25 × 60 = 75 m Increased breadth of rectangular field = 1.45 × 40 = 58 m Increased perimeter of rectangular field = 2 × (75 + 58) = 266 m Required percentage increase = {(266 – 200)/200} × 100 = 33%
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...3.934 - 124.07 + 35.94 + 12.83 of 4.85 - 84.76 ÷ √26 = ?3
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1680.23 ÷ 27.98) + (600.32 ÷ 23.9) + 1384.11 = ?
What approximate value should replace the question mark?
27.48% of 600.06 + ?% of 200.01 = 284.94
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
2090.03 ÷ 54.98 x 49.9 = ? + 20.32
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
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