Question
What is the total surface area of a pyramid whose base is square with a side of 8 cm and the height of the pyramid is 3 cm?
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The side of the square = 8cm and the height of the pyramid =3cm Now the area of the base = (8) ²= 64m² And perimeter = 4 × 8 = 32cm Slant height= l² = h² + (BC /2) ² l² = 9+16 =25 l = 5cm The total surface area of the pyramid = (1/2× perimeter of base ×slant height) + area of base = (½ ×32×5) +64 = 80+64 =144cm