Question
The rectangular park has a length-to-breadth ratio of
8:7. Its perimeter exceeds the perimeter of a square-shaped park by 40 meters. The side length of the square park is 4 meters less than the breadth of the rectangular park. Determine the area of the rectangular park.Solution
Let, length and breadth of the rectangular park be β8yβ m and β7yβ m, respectively. So, 2 Γ (8y + 7y) β 4 Γ (7y β 4) = 40 30y β 28y + 16 = 40 2y = 24 y = 12 Therefore, area of rectangular park = 56y2 = 8064 m2
- Determine the final value of this expression:
(1/5) of {5β΄ - 24 Γ 14 + 12 Γ 18 - 10.5 of 10Β²} 3% of 842 ÷ 2% of 421 = ?
β225 + 27 Γ 10 + ? = 320
- Determine the value of βpβ if p = β529 + β1444
45 % of 180 + β144 * 8 = ?2 Β + 70 % of 80
Determine the value of 'p' in following expression:
720 Γ· 9 + 640 Γ· 16 - p = β121 X 5 + 6Β²- 7?2 = β20.25 Γ 10 + β16 + 32
- What will come in place of the question mark (?) in the following questions?
(2β΄ + 6Β²) Γ· 2 = ? 18(1/3) + 9(2/3) β 10(1/3) = 1(2/3) + ?