Question
The length of a rectangle is 9 metres more than its
width. If the perimeter of the rectangle is 62 metres then what is the area (in m2Â ) of the rectangle?Solution
Let the width of the rectangle = ‘x’ metres Then, length of the rectangle = (x + 9) metres Perimeter of the rectangle = 2 × (length + width) Or, 2 × (x + x + 9) = 62 Or, 2x + 2x + 18 = 62 Or, 4x = 62 – 18 = 44 Or, x = 44/4 = 11 m So, area of the rectangle = x × (x + 9) = 11 × 20 = 220 m2
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