📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 12:11, respectively and it has a perimeter of 92 metres. If a triangular piece with height of 9 metres and base of 10 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 453 Correct Answer Incorrect Answer
    B 463 Correct Answer Incorrect Answer
    C 493 Correct Answer Incorrect Answer
    D 483 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be ‘12x’ metres and ‘11x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (12x + 11x) = 46 x metres So, 46x = 92 So, x = (92/46) = 2 So, area of the entire paper = length × breadth = (12 × 2) × (11 × 2) = 24 × 22 = 528 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 9 × 10 = 45 m2 So, area of the remaining paper = 528 – 45 = 483 m2

    Practice Next
    More Mensuration Questions

    Relevant for Exams:

    ask-question