Question
There is a rectangular paper, whose length and breadth are in the ratio 9:5, respectively and it has a perimeter of 84 metres. If a triangular piece with height of 10 metres and base of 18 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
Solution
Let the length and breadth of the rectangular be ‘9x’ metres and ‘5x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (9x + 5x) = 28 x metres So, 28x = 84 So, x = (84/28) = 3 So, area of the entire paper = length × breadth = (9 × 3) × (5 × 3) = 27 × 15 = 405 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 10 × 18 = 90 m2 So, area of the remaining paper = 405 – 90 = 315 m2
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