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ATQ,
Length of cuboid = 6 × 5 = 30 cm
Breadth of cuboid = 5 cm
Height of cuboid = 5 cm
Total surface area of cuboid = 2 × (lb + bh + hl), where 'l', 'b' and 'h' are
length, breadth and height respectively
So, required area = 2 × (30 × 5 + 5 × 5 + 5 × 30)
= 2 × (150 + 25 + 150)
= 2 × 325
= 650 cm²
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