Question
The greatest number of four digits which when divided by
5, 7, 9 leave remainders 3, 5, 7 respectively is:Solution
The difference between divisor and the corresponding remainder is equal (i.e 2). LCM of 5, 7 and 9 = 315 Largest 4-digit number = 9999 After dividing 9999 by 315 we will get the remainder as 234. Therefore, the number divisible by 315 = 9999 β 234 = 9765 If 2 is subtracted from the number 9765 the resulting number will follow the condition in the question and that number is 9763.
Find remainder when 7ΒΉΒ³ is divided by 100.

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