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Area of the track = length of track x breadth of track = 10 x breadth of track = 3600 So, breadth of track = 3600 ÷ 20 = 360 So, perimeter of the track = (10 + 360) x 2 = 740 metres So, speed of the car = (740/20) = 37 m/s Relative speed of the car with respect to the person = 37 + 5 = 42 m/s So, distance between the car and the person, 3 seconds before they cross each other = 42 x 3 = 126 metres
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