Question
Two cones X and Y of are melted together to form a
cylinder of height 48 m. The height of cones X and Y are in the ratio of 3:2 respectively and the radius of cone X is 5/6 of the radius of cone Y. The curved surface area of cylinder is 2112 cm 2 .Which of the following can be determined?I: Radius of cylinderII: Total surface area of cone XIII: Relation between radius and height of cone.Solution
Curved surface area of cylinder = 2112 cm 2
2 * 22/7 * R * 48 = 2112
R = 7 cm
Let height of cone X and Y are '3h' cm and '2h' cm respectively and radius of cone X and Y are '5r' cm and '6r' cm respectively.
1/3 * Ο [25r 2 Β *3h + 36r 2 Β *2h] = Ο*7*7*48
r 2 h = 48
I: Radius of cylinder = 7 cm
II: Total surface area of cone X cannot be determined.
III: Relation between radius and height of cone = r 2 h = 48 cm 3
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