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ATQ, Let length and breadth of the rectangle be ‘L’ cm and ‘B’ cm Initial area = (L × B) cm² Increased length and breadth = ‘2L’ cm and ‘3B/4’ cm Increased area = {2L × (3B/4)} = {(3 × L × B)/2} cm² Required percentage = {(1.5LB – LB)/LB} × 100 = 50%