Question
A cylindrical pencil of diameter 1.2 cm has one of its
end sharpened into a conical shape of height 1.4 cm. The volume of the material removed isSolution
= πr2h – 1/3 πr2 h = 2/3 πr2 {r = (1.2/2) = 0.6, h = 1.4} 2/3 × 22/7 × 0.62 × 1.4 = 2 × 22 × 0.2 × 0.2 × 0.6 = 1.056 cm3
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