Question
A cylindrical pencil of diameter 1.2 cm has one of its
end sharpened into a conical shape of height 1.4 cm. The volume of the material removed isSolution
= Οr2h β 1/3 Οr2 h = 2/3 Οr2 Β {r = (1.2/2) = 0.6, h = 1.4} 2/3 Γ 22/7 Γ 0.62 Γ 1.4 = 2 Γ 22 Γ 0.2 Γ 0.2 Γ 0.6 = 1.056 cm3
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