Question
If the areas of three adjacent faces of a rectangular
box which meet in a corner are 12cm2, 15cm2 and 20cm2 respectively. Then the volume of the box isSolution
let length , breadth , height be l, b, h respectively l × b = 12 ------------- eq 1 b × h = 15---------------eq2 h × l = 20----------------eq3 multiply eq 1 by eq2 and dividing eq3 we get (l×b×b×h)/ h×l = b2 = (12×15)/20 b = 3 from eq 1 we get l = 4 from eq 2 we get h = 5 volume of the cuboid = l × b × h = 3 × 4 × 5 = 60 cm3 Â
60   61    57   66    ?      75    39
...15   8   9   15   32    ?    250.5
What will come in place of the question mark (?) in the following series?
4000, ?, 320, 192, 153.6, 153.6
- What will come in place of the question mark (?) in the following series?
121, 115, 102, 82, 55, ? 10Â Â Â 11Â Â Â Â 12Â Â Â Â 20Â Â Â Â 24Â Â Â Â ?
23Â Â Â Â 40Â Â Â Â Â Â 67 Â Â Â Â Â Â 104Â Â Â Â Â Â ? Â Â Â Â Â Â 208
...64, 65, 73, 100, ?, 289
12, 19, 33, ?, 117
312, 302, 282, ?, 212, 162
252, 235, 220, 207, 196, ?
