Question
If the areas of three adjacent faces of a rectangular
box which meet in a corner are 12cm2, 15cm2 and 20cm2 respectively. Then the volume of the box isSolution
let length , breadth , height be l, b, h respectively l Ă— b = 12 ------------- eq 1 b Ă— h = 15---------------eq2 h Ă— l = 20----------------eq3 multiply eq 1 by eq2 and dividing eq3 we get (lĂ—bĂ—bĂ—h)/ hĂ—l = b2 = (12Ă—15)/20 b = 3 from eq 1 we get l = 4 from eq 2 we get h = 5 volume of the cuboid = l Ă— b Ă— h = 3 Ă— 4 Ă— 5 = 60 cm3 Â
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