New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    A cone is cut parallel to its base in 3 parts in such a

    way that the height of each part is same. Find the ratio of volume of these parts?
    A 1 : 8 : 27 Correct Answer Incorrect Answer
    B 1 : 2 : 4 Correct Answer Incorrect Answer
    C 1 : 7 : 19 Correct Answer Incorrect Answer
    D 1 : 4 : 9 Correct Answer Incorrect Answer

    Solution

    Volume of cone ABC = 1/3 π(r1)2h ............(1) Volume of Frustrum BCED = 1/3 π(2r1)22h - 1/3 π(r1)2h = 7/3 π(r1)2h ............(2) Volume of Frustrum DEGF = 1/3 π(3r1)23h - 1/3 π(2r1)22h = 19/3 π(r1)2h ............(3) Now, ratio = 1/3 π(r1)2h : 7/3 π(r1)2h : 19/3 π(r1)2h = 1:7:19

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