Question
If x = 555, y = 554, z = 556, then the value of
x2 + y2 + z2 - xy-yz-zx ÂSolution
x2 + y2 + z2 - xy-yz-zx = 1/2 {(x-y)2+(y-z)2+(z-x)2 } = 1/2 {(555-554)2+(554-556)2+(556-555)2 } = 1/2 {(1)2+(-2)2+(1)2 } = 1/2 (1 + 4 + 1) = 1/2 × 6 = 3
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(A) A1
(B) A2
(C) A3
(D) A0
(E) A00
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