I. 2p2 + 5p + 2 = 0               II.

Solution

I. 2p² + 5p + 2 = 0   (2p + 1) (p + 2) = 0   p = - (1/2)  or -2   II. 2q² + 11 q + 14 = 0   (q + 2) (2q + 7) = 0   q = -2 or - (7 /2)   Hence, p ≥ q   Alternate Method:   if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve. So, roots of first equation = p = -1/2, -2 if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve.  So, roots of second equation = q = -2, -7/2 After comparing roots of quadratic eqution we can conclude that p ≥ q.