Question
For given pair of equations, how many solutions are
possible? 2x + 3y = 10 and 4x + 5y = 18Solution
For a pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, only one solution is possible when (a1/a2) ≠(b1/b2) In the given pair of equations, a1 = 2, a2 = 4, b1 = 3 and b2 = 5 Since, (2/4) ≠(3/5), therefore, only one solution is possible.
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