Question
For given pair of equations, how many solutions are
possible? 7x − 3y = 20 and 14x − 5y = 40Solution
For a pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, only one solution is possible when (a1/a2) ≠ (b1/b2) In the given pair of equations, a1 = 7, a2 = 14, b1 = −3 and b2 = −5 Since, (7/14) ≠ (−3/−5), therefore, only one solution is possible.
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