Question
The angle of elevation of an aeroplane from a point on
the ground is 60Ā°. After 15 seconds flight the elevation changes to 30Ā°, if the aeroplane is flying at a height of 2400ā3 m. find the speed of the aeroplane.Solution
Distance between two place in which angle change isĀ D = n(cotĪøā + cotĪøā) Distance = 2400ā3 (cot30Ā° + cot60Ā°) = 2400ā3 Ć ā3 - 1/ā3Ā = 2400ā3 Ć 2/ā3 = 4800 m So, distance covered by plane in 15 sec = 4800 m Speed of plane = 4800/15 = 320 m/sec.
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