Question
A certain number of students from school X appeared in
an examination and 30% students failed. 150% more students than those from school X, appeared in the same examination from school Y. If 80% of the total number of students who appeared from both the schools passed, then what is the percentage of students who failed from Y?Solution
Number of students failed in school X = 30% Number of students in school Y = 150% more than number of students in school X Students passed in both schools = 80% Let number of students in school X be 100x. Number of failed students in school X = 30% of 100x = 30x Number of passes students in school Y = (100x – 30x) = 70x Number of students in school Y = 100x + 150% of 100x = 100x + 150x = 250x Total number of students in school X and school Y = 100x + 250x = 350x Number of passes students in both schools = 80% of 350x = 280x So, number of passed students in school Y = 280x – 70x = 210x Number of failed students in school Y = 250x – 210x = 40x Percentage of failed students in school Y = (40x/250x) × 100% = 16% ∴ The percentage of students who failed from school Y is 16%.
The number of marbles with ‘Ankit’ and ‘Bhavya’ together is 25 more than that with ‘Chetan’, while the number of marbles with ‘Bhavya’ a...
The sum of three numbers in AP is 21, and their product is 315. Find the numbers.
The 11th term of an AP is 80 less than the first term. If the second term is 88, find the third term.
what is the mean of given numbers 25, 15, 12, 23, 15,
The average weight of 16 people in a group is 75 kg. If the heaviest person who weighs 95 kg is replaced by a new person, and the average weight of the ...
The fourth term of an arithmetic progression is 6. Then the sum of first seven terms is:
If the median and mode of some observations is 5 and 9, respectively, then find the mean of those observations.
The sum to n terms of the series 1 + 1 + 3 + 1 + 3 + 5 + 1 + 3 + 5 + 7 …………………… is
‘479385A267’ is ten-digit number which is divisible by 9, what is the value of ‘A’?
If a, b, c are in geometric progression and a + b + c = 14, a² + b² + c² = 84, find a, b, c.