Question
The least number which when divided by 5, 15 and 25
leave a same remainder 2 in each case?Solution
The least number which divided by 5, 15 and 25 leaves a same remainder 2 in each case = LCM (5, 15 & 25) + same remainder = 75 + 2 = 77.
More HCF and LCM Questions
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. p2 – 15p + 56 = 0
II. q2 + 2q – 63 = 0
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. 2y2 + 31y + 99 = 0
II. 4x2 + 8x – 45 = 0
I. x² + 3x – 154 = 0
II. y² + 5y – 126 = 0
I. 2x2 - 15x + 25 = 0
II. 3y2 - 10y + 8 = 0
I. 6x² + 77x + 121 = 0
II. y² + 9y - 22 = 0
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
I. 2(x+2)+ 2(-x)=5
II. (1/(y+1)+ 1/(y+5))=(1/(y+2)+ 1/(y+4))