Question
Mohit starts from point Y and drives 6 km towards south.
He then takes a left turn, drives 23 km, turns right and drives 27 km. He then takes a right turn and drives 11 km. He takes a right turn, drives 13 km. He then turns right, drives 19 km, turns left and drives 20 km to stop at point Z. How far (shortest distance) and towards which direction should he drive in order to reach point Y again? (All turns are 90 degrees turns only unless specified.)ΒSolution
Place Y at the origin (0,0)(0,0) ( 0 , 0 ) . Take north as +y+y + y , east as +x+x + x .
Follow Mohitβs moves step by step:
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6 km south β (0,β6)(0,-6) ( 0 , β 6 )
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Left (facing south β left = east) 23 km β (23,β6)(23,-6) ( 23 , β 6 )
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Right (facing east β right = south) 27 km β (23,β33)(23,-33) ( 23 , β 33 )
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Right (facing south β right = west) 11 km β (12,β33)(12,-33) ( 12 , β 33 )
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Right (facing west β right = north) 13 km β (12,β20)(12,-20) ( 12 , β 20 )
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Right (facing north β right = east) 19 km β (31,β20)(31,-20) ( 31 , β 20 )
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Left (facing east β left = north) 20 km β (31,0)(31,0) ( 31 , 0 ) = point Z
So Z is at (31,0)(31,0) ( 31 , 0 ) and Y is at (0,0)(0,0) ( 0 , 0 ) . The displacement from Z to Y is (β31,0)(-31,0) ( β 31 , 0 ) , i.e. 31 km due west.
Answer: He must drive 31 km towards the west to return to point Y.
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