Question
The HCF of two numbers is 56, and their LCM is 1680.
What is the sum of the numbers?Solution
Let the two numbers be 56x and 56y.
Then,
Product of the numbers = Product of HCF and LCM
56x × 56y = 56 × 1680
xy = 30
Let x = 5 and y = 6 (As co-prime factors of 30 are 5 and 6).
Then, the sum of the numbers is
56 × 5 + 56 × 6 = 56 × 11 = 616
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