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    Question

    The sum and difference of L.C.M and H.C.F of two numbers

    are 294 and 126. If one of the numbers is 21, find the other number.
    A 840 Correct Answer Incorrect Answer
    B 744 Correct Answer Incorrect Answer
    C 639 Correct Answer Incorrect Answer
    D 826 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the L.C.M and the H.C.F of the two numbers be 'a' and 'b' respectively

    Then, (a + b) = 294

    And (a - b) = 126

    So, (a + b) + (a - b) = 294 + 126 = 420

    Or, a = 420 Ă· 2 = 210

    So, b = 294 - 210 = 84

    The product of two numbers is equal to the product of their L.C.M and H.C.FSo, required number = (210 Ă— 84) Ă· 21 = 840

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